# Solve for x. x^{2}-5x+6=0

Solve for x.
${x}^{2}-5x+6=0$
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Charles Benedict
Given:
${x}^{2}-5x+6=0$
Solving for x:
By factorization:
${x}^{2}-5x+6=0$
(x-3)(x+2)=0
x-3=0
x=3
x+2=0
x=-2
Therefore there is more than one solution x=3,-2