A standard table tennis ball has a diameter of 40 mm, weighs 2.7 g, and is made of a thin, spherical shell. What is its moment of inertia about an axis that passes through its center?

Question

kalfswors0m · Accepted Answer

You may calculate the ball&#039;s moment of inertia using equality:&amp;nbsp;I=23mr2&amp;nbsp;I&amp;nbsp;is the inertia of the tennis ball,&amp;nbsp;m&amp;nbsp;is the mass of the ball,&amp;nbsp;r&amp;nbsp;is a rafius of the ball.&amp;nbsp;d=40mm,&amp;nbsp;m=2.7g&amp;nbsp;Calculating the radius:&amp;nbsp;r=12d=12×40×10−3m=0.02m&amp;nbsp;m=2.7g×10−3kg=0.0027kg&amp;nbsp;Substitute the values to the formula:&amp;nbsp;I=23×0.0027kg×(0.02m)2=7.2×10−7kg×m2

xandir307dc · Accepted Answer

Good job, thanks!

A regulation table tennis ball is a thin spherical shell

Answered question

Answer & Explanation

New Questions in Other