# How do you write an equation of a line with

How do you write an equation of a line with point (2,5), slope -2?
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Terry Ray
Point slope form of a line is the standard equation:
$y-{y}_{1}=m\left(x-{x}_{1}\right)$
where ${x}_{1}$ and ${y}_{1}$ are a point the line intersects and m in the slope, so your line:
$y-5=-2\left(x-2\right)$ is your line.
you can convert it to slope intercept form:
$y=-2x+9$
so the slope $m=-2$ and the y-intercept is 9

Jillian Edgerton
We must assume that the line is a straight line.
The equation of a straight line in slope/point form is:
$\left(y-{y}_{1}\right)=m\left(x-{x}_{1}\right)$
Where the line has a slope m and passes through the point $\left({x}_{1},{y}_{1}\right)$
Here we have a line of slope -2 passing through the point (2,5)
$\therefore \left(y-5\right)=2\left(x-2\right)$
$y=-2x+4+5$
$y=-2x+9$
is the equation of the line in slope/intercept form.