# How do you find the exact value of \cos^{-1}0

How do you find the exact value of ${\mathrm{cos}}^{-1}0$
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Louis Page
Explanation:
${\mathrm{cos}}^{-1}=-\mathrm{arccos}0$
What is the arc which cosine is zero?: two posibilities $90=\frac{\pi }{2}$ and $270=3\frac{\pi }{2}$
This is assuming that ${\mathrm{cos}}^{-1}$ is the inverse of cosine. There is no missunderstanding if use $\mathrm{arccos}$ instead of ${\mathrm{cos}}^{-1}$ Because ${\mathrm{cos}}^{-1}$ is also understud as $\frac{1}{\mathrm{cos}}=\mathrm{sec}$ which is different
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Heather Fulton
The trig ratios are defined as ratios of side lengths of a right-angled triangle. $\mathrm{cos}$ is the adjacent side divided by the hypotenuse, i.e. the length of the short side next to the angle being considered divided by the length of the long side next to it that isnt