veksetz
2021-12-15
Answered

How do you solve for x in $ax-c=b$ ?

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Raymond Foley

Answered 2021-12-16
Author has **39** answers

First, add c to each side of the equation to isolate the x term while keeping the equation balanced:

$ax-c+c=b+c$

$ax-0=b+c$

$ax=b+c$

Now, divide each side of the equation by a to solve for x while keeping the equation balanced:

$\frac{ax}{a}=\frac{b+c}{a}$

$\frac{ax}{a}=\frac{b+c}{a}$

$x=\frac{b+c}{a}$

Or

$x=\frac{b}{a}+\frac{c}{a}$

Now, divide each side of the equation by a to solve for x while keeping the equation balanced:

Or

Melissa Moore

Answered 2021-12-17
Author has **32** answers

Add c in both sides, we get ax - c + c = b + c

$\Rightarrow ax=b+c$

$\Rightarrow \frac{ax}{a}=\frac{b+c}{a}$

$\Rightarrow x=\frac{b+c}{a}$

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I know the argument of the function has to be greater than 0, so:

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$\begin{array}{rl}& \left(\frac{x}{x-1}\right)>0\\ & x>0\end{array}$

however in this case $x\ne 1$, $x\ne 0$ as they result in an answer which is undefined, so I think it's reasonable for me to say the domain is $x>1$, however this is not the correct answer.

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Leave the answer in polar form.

and

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