# How do you solve for x in ax-c=b ?

How do you solve for x in $ax-c=b$ ?
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Raymond Foley
First, add c to each side of the equation to isolate the x term while keeping the equation balanced:
$ax-c+c=b+c$
$ax-0=b+c$
$ax=b+c$
Now, divide each side of the equation by a to solve for x while keeping the equation balanced:
$\frac{ax}{a}=\frac{b+c}{a}$
$\frac{ax}{a}=\frac{b+c}{a}$
$x=\frac{b+c}{a}$
Or
$x=\frac{b}{a}+\frac{c}{a}$
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Melissa Moore
Add c in both sides, we get ax - c + c = b + c
$⇒ax=b+c$
$⇒\frac{ax}{a}=\frac{b+c}{a}$
$⇒x=\frac{b+c}{a}$