 # How do you factor 2x^2-x-3 ? pierdoodsu 2021-12-17 Answered
How do you factor $2{x}^{2}-x-3$ ?
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$2{x}^{2}-x-3=\left(2x-3\right)\left(x+1\right)$
since it is $2{x}^{2}$
in one of the brackets there must be a x with coefficient 2
$\left(2x\dots \right)\left(x\dots \right)$
next think how 3, 2, 1 (coefficients of respectively) relate to each other (using addition and subtraction)
$3-2=1$
what makes 3 and 2 and 1? using multiplication
$3\cdot 1=3$
$2\cdot 1=2$
Now we have clearer idea on what to do
$\left(2x-3\right)\left(x+1\right)$
there you go
If you are having difficulties to factorise (provided that the equation is factorisable), don't frustrate. You just need more practices.
###### Not exactly what you’re looking for? Medicim6
Explanation:
$2{x}^{2}-x-3$
$=2{x}^{2}-3x+2x-3$
$=x\left(2x-3\right)+1\left(2x-3\right)$
$=\left(x+1\right)\left(2x-3\right)$