How do you factor 2x^2-x-3 ?

How do you factor $2{x}^{2}-x-3$ ?
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Annie Gonzalez
$2{x}^{2}-x-3=\left(2x-3\right)\left(x+1\right)$
since it is $2{x}^{2}$
in one of the brackets there must be a x with coefficient 2
$\left(2x\dots \right)\left(x\dots \right)$
next think how 3, 2, 1 (coefficients of respectively) relate to each other (using addition and subtraction)
$3-2=1$
what makes 3 and 2 and 1? using multiplication
$3\cdot 1=3$
$2\cdot 1=2$
Now we have clearer idea on what to do
$\left(2x-3\right)\left(x+1\right)$
there you go
If you are having difficulties to factorise (provided that the equation is factorisable), don't frustrate. You just need more practices.
Not exactly what you’re looking for?
Medicim6
Explanation:
$2{x}^{2}-x-3$
$=2{x}^{2}-3x+2x-3$
$=x\left(2x-3\right)+1\left(2x-3\right)$
$=\left(x+1\right)\left(2x-3\right)$