Two in-phase loudspeakers emit identical 1000 Hz sound waves along

osnomu3 2021-12-15 Answered
Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. What distance should one speaker be placed behind the other for the sound to have an amplitude 1.20 times that of each speaker alone?
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Expert Answer

temnimam2
Answered 2021-12-16 Author has 36 answers
Solution:
Consider the formula to findout the wavelength is,
λ=vf
Substute 343 ms for v and 1000Hz for f in equation
λ=3.43 ms1000 Hz
λ=0.343 m
Consider the formula to find the amplitude of the wave formed due to two waves with same frequency
A=2acos(ϕ2)
Here, ϕ=2πxλ
Therefore,
A=2acos((2πxλ)2)
Substitute (1.20×a) for A and 0.343 m for λ in equation
1.20a=2acos((2πxλ)2)
x=0.343mπcos1(1.202)
x=5.79 Cm
Thus, the distance that one speaker be placed behind the other for the sound to have an amplitude 1.20 times that of each speaker alone is x=5.79

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ramirezhereva
Answered 2021-12-17 Author has 28 answers
I could not find the answer, thanks!

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