Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. What distance should one speaker be placed behind the other for the sound to have an amplitude 1.20 times that of each speaker alone?

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temnimam2 · Accepted Answer

Solution:  Consider the formula to findout the wavelength is,  λ=vf  Substute 343 ms for v and 1000Hz for f in equation   λ=3.43 ms1000 Hz  λ=0.343 m  Consider the formula to find the amplitude of the wave formed due to two waves with same frequency  A=2acos⁡(△ϕ2)  Here, △ϕ=2π△xλ  Therefore,  A=2acos⁡((2π△xλ)2)  Substitute (1.20×a) for A and 0.343 m for λ in equation  1.20a=2acos⁡((2π△xλ)2)  △x=0.343mπcos−1(1.202)  △x=5.79 Cm  Thus, the distance that one speaker be placed behind the other for the sound to have an amplitude 1.20 times that of each speaker alone is △x=5.79

ramirezhereva · Accepted Answer

I could not find the answer, thanks!

Two in-phase loudspeakers emit identical 1000 Hz sound waves along

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