A polynomial P is given. P(x)=x^{4}+16x^{2} (a) Find all zeros of P,

eliaskidszs

eliaskidszs

Answered question

2021-12-17

A polynomial P is given.
P(x)=x4+16x2
(a) Find all zeros of P, real and complex.

Answer & Explanation

Cleveland Walters

Cleveland Walters

Beginner2021-12-18Added 40 answers

Step 1
Given polynomial, P(x)=x4+16x2
Step 2
Zeroes of P(x), P(x)=0
x4+16x2=0
x2(x2+16)=0
x2=0 & x2+16=0
x=0,0 & x2=16
x=0,0 & x=±4i
Hence zeroes are x=0,±4i
scomparve5j

scomparve5j

Beginner2021-12-19Added 38 answers

Sol: Given P(x)=x4+16x2
(a) Then P(x)=x4+16x2=0
x2(x2+16)=0
x2(x+4i)(x4i)=0
x=0,0,x+4i=0,x4i=0
x=0,0,x=4i,x=4i
x=0,0,4i,4i
Zeroes are 0,0, -4i, 4i

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