A polynomial P is given. P(x)=x^{4}+16x^{2} (a) Find all zeros of P,

eliaskidszs 2021-12-17 Answered
A polynomial P is given.
P(x)=x4+16x2
(a) Find all zeros of P, real and complex.
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

Cleveland Walters
Answered 2021-12-18 Author has 40 answers
Step 1
Given polynomial, P(x)=x4+16x2
Step 2
Zeroes of P(x), P(x)=0
x4+16x2=0
x2(x2+16)=0
x2=0 & x2+16=0
x=0,0 & x2=16
x=0,0 & x=±4i
Hence zeroes are x=0,±4i

We have step-by-step solutions for your answer!

scomparve5j
Answered 2021-12-19 Author has 38 answers
Sol: Given P(x)=x4+16x2
(a) Then P(x)=x4+16x2=0
x2(x2+16)=0
x2(x+4i)(x4i)=0
x=0,0,x+4i=0,x4i=0
x=0,0,x=4i,x=4i
x=0,0,4i,4i
Zeroes are 0,0, -4i, 4i

We have step-by-step solutions for your answer!

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions