# Simplify the expression, please: \sin(\arctan(x))

$\mathrm{sin}\left(\mathrm{arctan}\left(x\right)\right)$
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Louis Page

$\mathrm{arctan}\left(x\right)=\frac{x}{1}$
Considering the sides of the right triangle. We have , and $hypotenuse=\sqrt{{x}^{2}+1}$
Therefore the sine of this angle

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