# What is 15x^{2}+17x+4=0 in factor form?

What is $15{x}^{2}+17x+4=0$ in factor form?
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habbocowji
$15{x}^{2}+17x+4=0$
$15{x}^{2}+5x+12x+4=0$
$5x×3x+5x×1+12x+4=0$
$5x\left(3x+1\right)+12x+4=0$
$5x\left(3x+1\right)+4×3x+4×1=0$
$5x\left(3x+1\right)+4\left(3x+1\right)=0$
$\left(5x+4\right)\left(3x+1\right)=0$
Now, to solve for x, make each of these factors equal to 0 to find out what the x value will be:
$5x+4=0$
$5x=-4$
$x=-\frac{4}{5}$
And $3x+1=0$
$3x=-1$
$x=-\frac{1}{3}$
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veiga34
$15{x}^{2}+17x+4=0$
$15{x}^{2}+5x+12x+4=0$
$5x×3x+5x×1+4×3x+4×1=0$
$5x\left(3x+1\right)+4\left(3x+1\right)=0$
$\left(5x+4\right)\left(3x+1\right)=0$
$5x+4=0$
$5x=-4$
$x=-\frac{4}{5}$
And $3x+1=0$
$3x=-1$
$x=-\frac{1}{3}$