Suppose f(x) = 0.125x for 0 < x < 4.

socorraob

socorraob

Answered question

2021-12-12

Suppose f(x)=0.125x for 0<x<4. determine the mean and variance of X.

Answer & Explanation

Hector Roberts

Hector Roberts

Beginner2021-12-13Added 31 answers

Mean [E(x)] of x 
The mean formula is given by,
E(x)=xf(x) dx  
=40x0.125x dx  
=40x20.125x dx  
=0.125=40x2 dx  
=0.125[x33]04 {since xn dx =xn+1n+1
=0.125[4330] 
=0.125(643) 
E(x)=83 or 2.667

Bertha Jordan

Bertha Jordan

Beginner2021-12-14Added 37 answers

The formula for varience of x is given by,
Varience(x)= E[x2][E[x]]2
to find E[x2]:
E[x2]=xx2f(x)dx
=04x20.125xdx
=04x30.125dx
=0.12504x3dx
=0.125[x4x]04sincePSKxndx=(xn+1)n+1}
=0.125[4440]
=0.12543
E[x2]=8
Thus =E[x2][E[x]]2
We know that E[x2]=8 and E[x]=2.667
Thus =8(2.667)2
=87.113
=0.887
Varriance of x 0.887

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