chezmarylou1i
2021-12-17
Answered

How do you write 0.09 as a fraction?

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asked 2022-07-08

Find all integer numbers n such that $\frac{11n-5}{n+4}$ is a perfect square.

Find all integer numbers n, such that,

$\sqrt{\frac{11n-5}{n+4}}\in \mathbb{N}$

I really tried but I couldn't guys, help please.

Find all integer numbers n, such that,

$\sqrt{\frac{11n-5}{n+4}}\in \mathbb{N}$

I really tried but I couldn't guys, help please.

asked 2022-09-20

How to isolate algebraic fraction in this case

i have a question about of how to isolate an equation, when it has a multiplication in the denominator.

a/b/3 is same than a*(3/b)

but, when is:

a/(b/3 * 4/a)

If i want to isolate the 4/a that is multiplying the b/3 and in turn dividing to a, so how isolate only the 4/a ?

i have a question about of how to isolate an equation, when it has a multiplication in the denominator.

a/b/3 is same than a*(3/b)

but, when is:

a/(b/3 * 4/a)

If i want to isolate the 4/a that is multiplying the b/3 and in turn dividing to a, so how isolate only the 4/a ?

asked 2021-11-16

In the following exercises, find the least common denominator (LCD) for each set of fractions.

$\frac{21}{35}\text{}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\text{}\frac{39}{56}$

asked 2022-09-30

What is the recommended method to simplify trigonometric expressions like $\frac{\mathrm{sin}\alpha -\mathrm{sin}\beta}{\mathrm{cos}\alpha -\mathrm{cos}\beta}$?

I tried to manipulate them using double and sum but none of them seemed to help.

I tried to manipulate them using double and sum but none of them seemed to help.

asked 2021-11-12

Change the mixed expressions to fractions.

$y+\frac{2{y}^{3}}{{x}^{3}-{y}^{3}}$

1)$2{y}^{4}$

2)$\frac{{x}^{3}y+2{y}^{3}-{y}^{4}}{{x}^{3}-{y}^{3}}$

3)$\frac{2{y}^{3}+y}{{x}^{3}-{y}^{3}}$

1)

2)

3)

asked 2020-11-23

Modeling: Draw models to represents $\frac{3}{4}$ and $2\left(\frac{3}{5}\right)$ .

asked 2022-07-15

Can the powers of 2 in the denominators of a fraction sum be used to find a contradiction?

Let ${a}_{1},{a}_{2},{b}_{1},{b}_{2},{c}_{1},{c}_{2},{d}_{1},{d}_{2},{e}_{1},{e}_{2}$ be odd integers, with

$gcd({a}_{1},{a}_{2})=gcd({b}_{1},{b}_{2})=gcd({c}_{1},{c}_{2})=gcd({d}_{1},{d}_{2})=gcd({e}_{1},{e}_{2})=1,$

and assume $n\ge 3$ and $m\ge 1$ are integers such that

$\begin{array}{}\text{(}\star \text{)}& \frac{{a}_{1}}{{2}^{3(n-1)m}{a}_{2}}+\frac{{b}_{1}}{{2}^{3((n-1)m+1)}{b}_{2}}+\frac{{c}_{1}}{{2}^{3((n-1)m+1)}{c}_{2}}+\frac{{d}_{1}}{{2}^{3nm}{d}_{2}}+\frac{{e}_{1}}{{2}^{3nm}{e}_{2}}=1.\end{array}$

Is there a way to prove, using only the powers of 2 in the set of denominators, that (⋆) is impossible?

Let ${a}_{1},{a}_{2},{b}_{1},{b}_{2},{c}_{1},{c}_{2},{d}_{1},{d}_{2},{e}_{1},{e}_{2}$ be odd integers, with

$gcd({a}_{1},{a}_{2})=gcd({b}_{1},{b}_{2})=gcd({c}_{1},{c}_{2})=gcd({d}_{1},{d}_{2})=gcd({e}_{1},{e}_{2})=1,$

and assume $n\ge 3$ and $m\ge 1$ are integers such that

$\begin{array}{}\text{(}\star \text{)}& \frac{{a}_{1}}{{2}^{3(n-1)m}{a}_{2}}+\frac{{b}_{1}}{{2}^{3((n-1)m+1)}{b}_{2}}+\frac{{c}_{1}}{{2}^{3((n-1)m+1)}{c}_{2}}+\frac{{d}_{1}}{{2}^{3nm}{d}_{2}}+\frac{{e}_{1}}{{2}^{3nm}{e}_{2}}=1.\end{array}$

Is there a way to prove, using only the powers of 2 in the set of denominators, that (⋆) is impossible?