# The first four term of sequeces A,B,C,D are shown Sequence A {(1/3),(2/4),(3/5),(4/6)}

The first four term of sequeces A,B,C,D are shown
Sequence A $\left(1/3\right),\left(2/4\right),\left(3/5\right),\left(4/6\right)$
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Step 1:
We know that a sequence isa function from nautral number to real number.
Let,(:${a}_{n}$:)be a sequence the required sequence,
Then,
$\left(:{a}_{n}:\right)={a}_{1},{a}_{2},{a}_{3},{a}_{4}.....{a}_{n},...$
Given
${a}_{1}=\left(1/3\right)$
${a}_{2}=\left(2/4\right)$
${a}_{3}+\left(3/5\right)$
${a}_{4}\left(4/6\right)$
${a}_{5}=\left(5/7\right)$
then, the ${n}^{th}$ sequence (:${a}_{n}$:) is given by
${a}_{n}=\frac{n}{n+2}$
now verify
for $n=1,{a}_{1}=\frac{1}{1+2}=\frac{1}{3}$
for $n=2,{a}_{2}=\frac{2}{2+2}=\frac{2}{4}$
for $n=3,{a}_{3}=\frac{3}{3+2}=\frac{3}{5}$
for $n=4,{a}_{4}=\frac{4}{4+2}=\frac{4}{6}$