What are the roots of the equation x^2-5x+1=0 ?

guringpw

guringpw

Answered question

2021-12-15

What are the roots of the equation x25x+1=0 ?

Answer & Explanation

lalilulelo2k3eq

lalilulelo2k3eq

Beginner2021-12-16Added 38 answers

You can solve this equation using 2 methods, one being completing the square method, and the other by using the quadratic formula.
1) Commencing completing the square method,
x25x+1=0
Subtract 1 on both sides,
x25x=1
Add 6.25 on both sides,
x25x+6.25=1+6.25
Apply perfect quadratic square formula,
(x2.5)2=5.25
Square root both sides,
x2.5=±5.25
Add 2.5 to both sides,
x=±5.25+2.5
Hence,
x=4.79128784 or 0.20871215
2) Commencing quadratic formula method,
x25x+1=0
Quadratic equation,
ax2+bx+c=0
Substitute a=1,b=5,c=1 into the quadratic formula.
x=5±212
Hence,
x=4.79128784 or 0.20871215
censoratojk

censoratojk

Beginner2021-12-17Added 46 answers

Find the roots:
x25x+1=0 quadratic equation
The standard form for a quadratic equation is ax2+bx+c=0, where a=1,b=5 and c=1. Note: a0
Solve this quadratic equation using the quadratic formula:
x=b±b24ac2a
Substitute the known values into the formula.
x=(5)±(5)241121
Simplify.
x=5±2542
Simplify.
x=5±212
Solutions for x. roots
x=5+212,5212

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