\((0.25(3+a))/0.25=(0.5)/(0.25)\)

3+a=2

3+a-3=2-3

checking

0.25(3+a)=0.5

0.25(3+(-1))=0.5

0.25(2)=0.5

0.5=0.5

a=-1

3+a=2

3+a-3=2-3

checking

0.25(3+a)=0.5

0.25(3+(-1))=0.5

0.25(2)=0.5

0.5=0.5

a=-1

Question

asked 2021-03-02

Solve the following equations and inequalities for x. Check your solution(s), if possible
\(a. \frac{3}{x}=9\)

\(b. \sqrt x=4\)

\(c. x^{2}=25\)

\(d. 2(x−3)>4\)

\(b. \sqrt x=4\)

\(c. x^{2}=25\)

\(d. 2(x−3)>4\)

asked 2021-02-02

Solve the following equations and inequalities for x. Check your solution(s), if possible
\(\displaystyle{a}.{\frac{{{3}}}{{{x}}}}={9}\)

\(\displaystyle{b}.\sqrt{{x}}={4}\)

\(\displaystyle{c}.{x}^{{{2}}}={25}\)

\(\displaystyle{d}.{2}{\left({x}−{3}\right)}{>}{4}\)

\(\displaystyle{b}.\sqrt{{x}}={4}\)

\(\displaystyle{c}.{x}^{{{2}}}={25}\)

\(\displaystyle{d}.{2}{\left({x}−{3}\right)}{>}{4}\)

asked 2021-02-08

Solve the equations and inequalities below. Check your solution(s), if possible.
\(a.300x-1500=2400\)

\(b.(3/2)^{x}=(5/6)^{x}+2\)

\(c.x^{2}-25\leq 0\)

\(d.|3x-2|>4\)

\(b.(3/2)^{x}=(5/6)^{x}+2\)

\(c.x^{2}-25\leq 0\)

\(d.|3x-2|>4\)

asked 2021-02-05

Solve the equations and inequalities below. Check your solution(s), if possible.
\(\displaystyle{a}{.300}{x}-{1500}={2400}\)

\(\displaystyle{b}.{\left(\frac{{3}}{{2}}\right)}^{{{x}}}={\left(\frac{{5}}{{6}}\right)}^{{{x}}}+{2}\)

\(\displaystyle{c}.{x}^{{{2}}}-{25}\leq{0}\)

\(\displaystyle{d}.{\left|{3}{x}-{2}\right|}{>}{4}\)

\(\displaystyle{b}.{\left(\frac{{3}}{{2}}\right)}^{{{x}}}={\left(\frac{{5}}{{6}}\right)}^{{{x}}}+{2}\)

\(\displaystyle{c}.{x}^{{{2}}}-{25}\leq{0}\)

\(\displaystyle{d}.{\left|{3}{x}-{2}\right|}{>}{4}\)

asked 2021-01-22

Solve the equation and check your solution.
\(\displaystyle\frac{{{20}−{2}{x}}}{{7}}=\frac{{{4}{x}+{9}}}{{8}}\)

asked 2020-12-17

Solve the equation. Check your solution. 21 = 4x - 9 - x

asked 2020-10-20

Solve the equations and inequalities below, if possible. Check your solutions.
\(a.(4x−2)^{2}≤100\)

\(b.(x−1)^{2}=9\)

\(c. x^{2}+x−20<0\)

\(d.2x^{2}−6x=−5\)

\(b.(x−1)^{2}=9\)

\(c. x^{2}+x−20<0\)

\(d.2x^{2}−6x=−5\)

asked 2021-02-03

Solve the equations and inequalities below, if possible. Check your solutions.
\(\displaystyle{a}.{\left({4}{x}−{2}\right)}^{{{2}}}≤{100}\)

\(\displaystyle{b}.{\left({x}−{1}\right)}^{{{2}}}={9}\)

\(\displaystyle{c}.{x}^{{{2}}}+{x}−{20}{<}{0}\)

\(\displaystyle{d}{.2}{x}^{{{2}}}−{6}{x}=−{5}\)

\(\displaystyle{b}.{\left({x}−{1}\right)}^{{{2}}}={9}\)

\(\displaystyle{c}.{x}^{{{2}}}+{x}−{20}{<}{0}\)

\(\displaystyle{d}{.2}{x}^{{{2}}}−{6}{x}=−{5}\)

asked 2020-12-13

solve each equation. check your answer. 20+g+g=14

asked 2021-02-25

Celine, Devon, and another friend want to purchase some snacks that cost a total of $7.50. They will share the cost of the snacks. Which of these statements is true?

A. An equation that can be used to find x, the amount of money each person will pay is x+3=7.5. The solution to the equation is 4.5, so each person will pay $4.50.

B. An equation that can be used to find x, the amount of money each person will pay is x+3=7.5. The solution to the equation is 10.5, so each person will pay $10.50.

C. An equation that can be used to find x, the amount of money each person will pay is x⋅3=7.5. The solution to the equation is 2.5, so each person will pay $2.50.

D. B. An equation that can be used to find x, the amount of money each person will pay is x⋅3=7.5. The solution to the equation is 22.5, so each person will pay $22.50.

A. An equation that can be used to find x, the amount of money each person will pay is x+3=7.5. The solution to the equation is 4.5, so each person will pay $4.50.

B. An equation that can be used to find x, the amount of money each person will pay is x+3=7.5. The solution to the equation is 10.5, so each person will pay $10.50.

C. An equation that can be used to find x, the amount of money each person will pay is x⋅3=7.5. The solution to the equation is 2.5, so each person will pay $2.50.

D. B. An equation that can be used to find x, the amount of money each person will pay is x⋅3=7.5. The solution to the equation is 22.5, so each person will pay $22.50.