Let \alpha = (1 7 3)(5 4 2 9)\ and\

Joseph Krupa 2021-12-10 Answered
Let α=(173)(5429) and B=(23)(74)(518) be ements of S10. Then, α2β1 is
(12794)(385)
(12749)(358)
(12794)(358)
(12974)(358)
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Expert Answer

scoollato7o
Answered 2021-12-11 Author has 26 answers
Step 1
elfa =(173)(5429)
(elfa)2=(173)(5429).(173)(5429)
that is (137)(52)(49) and beeta inverse will be (32)(47)(815)
that is (elfa)2.(β)1=(137)(52)(49).(32)(47)(815)
(12794)(358)
Step 2
so here option (b) is true
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Melinda McCombs
Answered 2021-12-12 Author has 38 answers
α=[1234567891079724789101]
β=[1234567891083271745101]
α2=[123456789107912473951]
[123456789107912473951]
α2=[123456789103579231547]
β1=[1234567891083271745101]
β1=[123456789105234847118]
α2β1=[123456789103579231547]
x=[123456789105234547118]
[1234579827813945]
α2β1(1 2 7 9 4)(3 8 5)
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