Let $\alpha =\left(173\right)\left(5429\right)\text{}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\text{}B=\left(23\right)\left(74\right)\left(518\right)\text{}be\text{}e\le ments\text{}of\text{}S10$ . Then, $\alpha}^{2}{\beta}^{-1$ is

$\left(12794\right)\left(385\right)$

$\left(12749\right)\left(358\right)$

$\left(12794\right)\left(358\right)$

$\left(12974\right)\left(358\right)$