Solve the following system of linear equation algebraically. 2x+3y=2 x-4y=12

Madeline Lott

Madeline Lott

Answered question

2021-12-10

Solve the following system of linear equation algebraically.
2x+3y=2
x4y=12

Answer & Explanation

Bertha Jordan

Bertha Jordan

Beginner2021-12-11Added 37 answers

Step 1
the given system of the equation as
2x+3y=2 (1)
x4y=12 (2)
Thus the equation (2) can be written as
x=12+4y (3)
Step 2
The value of equation (3) put in equation (1) as
2(12+4y)+3y=2
24+8y+3y=2
11y=224
11y=22
y=2211
y=2
Step 3
Now this value of y put in equation (3) as
x=12+4y
x=12+4.(2)
x=128
x=4
Hence the solution of the system is (x,y)=(4,2)
lovagwb

lovagwb

Beginner2021-12-12Added 50 answers

1) 2x+3y=2
2x3y=2
2x=2+3y
2x2=22+3y2
x=22+3y2
x=1+3y2
2) x4y=12
1x±4y=12
Add "4y" to each side of the equation.
1x±4y+4y=12+4y
Combine loke terms: 4y+4y=0
1x+0=12+4y
1x=12+4y
x=12±4y
x=12±4y

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