 # Mrs. Smith has a bank of 40 questions to use widdonod1t 2021-12-12 Answered
Mrs. Smith has a bank of 40 questions to use for the Foundations of Algebra exam. How many different final exams of 35 problems can she form (assuming the order of the questions does not matter)?
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Step 1
She has a bank of 40 questions out of which she has to choose 35 questions to make the final exams.
Also, the order of the Questions do not matter.
So, she can select 35 questions out of 40 questions in ${}^{\left\{40\right\}}{C}_{35}$ ways
Now, ${}^{\left\{40\right\}}{C}_{35}=40×39×38×37×36=658,008$
So, she can form the final exams in 658008 ways
###### Not exactly what you’re looking for? Bukvald5z
Step 1
She has 40 questions, of which she has to choose 35 for the final exams.
So,
${}_{\left\{40\right\}}{C}_{35}={2}^{3}×{3}^{2}×13×19×37$
$=658008$
Answer: she can shape final exams 658008 ways