Census reports for a city indicate that 62% of residents classify themselves as Christian, 12% as Jewish , and 16% as members of other religions (Musl

Ava-May Nelson

Ava-May Nelson

Answered question

2021-02-26

Census reports for a city indicate that 62% of residents classify themselves as Christian, 12% as Jewish, and 16% as members of other religions (Muslims, Buddhists, etc.).
The remaining residents classify themselves as nonreligious.
A polling organization seeking information about public opinions wants to be sure to talk with people holding a variety of religious views, and makes random phone calls. Among the first four people they call, what is the probability they reach

a) all Christians?

b) no Jews?

c) at least one person who is nonreligious?

Answer & Explanation

BleabyinfibiaG

BleabyinfibiaG

Skilled2021-02-27Added 118 answers

A) Apply the rule of multiplication:
P(allchristians)=62
B) The sum of all probabilities should be 100%:
P(not a jew) =100%12%=88%
Use the multiplication rule
P(nojews)=88
C) Apply the addition rule:
P(religious) =62%+12%+16%=90%
P(at least one non religious)=100%P(all religious) =100
Answer:
(a) 14.78%
(b) 59.97%
(c) 34.39%

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