# How to solve \ln(x+1)^{2}=2?

How to solve ${\mathrm{ln}\left(x+1\right)}^{2}=2$?
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Natalie Yamamoto
${\mathrm{ln}\left(x+1\right)}^{2}=2$
${\left(x+1\right)}^{2}={e}^{2}$
$x+1=e$
$x=e-1$
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Louis Page
${\mathrm{ln}\left(x+1\right)}^{2}=2$
$\mathrm{ln}\left(x+1\right)=1$
$x+1={e}^{1}=e$
$x=e-1$