# Find the values of the variables FSP01511100141.jpgFSZ

Find the values of the variables

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censoratojk

Solution:
$$\displaystyle\triangle{A}{B}{C}$$
$$\displaystyle{{\cos{{45}}}^{\circ}=}{\frac{{{9}}}{{{x}}}}$$
$$\displaystyle{x}={\frac{{{9}}}{{{\cos{{45}}}^{\circ}}}}$$
$$\displaystyle{x}={9}\sqrt{{2}}$$
$$\displaystyle{{\sin{{45}}}^{\circ}=}{\frac{{{y}}}{{{9}\sqrt{{2}}}}}$$
$$\displaystyle{y}={9}\sqrt{{2}}{{\sin{{45}}}^{\circ}\Rightarrow}{y}={9}$$
$$\displaystyle\triangle{A}{D}{C}$$
$$\displaystyle{{\sin{{45}}}^{\circ}=}{\frac{{{9}}}{{{z}}}}$$
$$\displaystyle{z}={9}\sqrt{{2}}$$
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Deufemiak7
Thank yo so much!