Consider the function f(x)=2-2x^{2}, -3\le x\le 1. The absolute maximum value

Deragz

Deragz

Answered question

2021-12-10

Consider the function f(x)=22x2,3x1.
The absolute maximum value is B
and this occurs at x= B
The absolute minimum value is B
and this occurs at x= B

Answer & Explanation

rodclassique4r

rodclassique4r

Beginner2021-12-11Added 37 answers

Step 1
f(x)=22x2   3x1
f'(x)=-4x
critical point -4x=0
x=0
Step 2
f(0)=2-2(0)
=2
at value of f(x) at end point
f(3)=22(3)2
=2-18=-16
f(1)=22(1)2
=2-2=0
absolute maxima value is 2 which occurs at x=0
absolute minimum value is -16 which occurs at x=1

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