Find the absolute value of the radian measure of the angle that the second hand of a clock moves through in the given time 4 minutes and 25 seconds.

David Young
2021-12-10
Answered

Find the absolute value of the radian measure of the angle that the second hand of a clock moves through in the given time 4 minutes and 25 seconds.

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Shannon Hodgkinson

Answered 2021-12-11
Author has **34** answers

Step 1

Degree & Radian:

The absolute value of the radian measure of the angle that the second hand of a clock moves through the time 4 mins

and 25 secs.

60 secs$=2\pi$

Step 2

60 secs$=2\pi$ radian

1 secs$=\frac{2\pi}{60}$ radian

25 secs$=\frac{2\pi \cdot 25}{60}$

$=\frac{5\pi}{6}$ radian

4 mins and 25 secs= 6.62 radian

Degree & Radian:

The absolute value of the radian measure of the angle that the second hand of a clock moves through the time 4 mins

and 25 secs.

60 secs

Step 2

60 secs

1 secs

25 secs

4 mins and 25 secs= 6.62 radian

asked 2022-06-11

I'm trying to solve a systems of equations problem but I can't seem to see what I'm doing wrong... As far as I can tell the way to solve a system of equations by substitution involves the following steps.

1. Isolate a variable in one of the equations

2. substitute that isolated variable into equation two so that you're second equation is in one variable

3. solve equation two for the second unknown variable

4. use the result from the second equation to find out what your original isolated variable equals.

here's my problem and what I tried:

equation 1: $1=A+B$

equation 2: $8=5A+2B$

Isolating $B$

$B=1-A$

Solving for $A$

$8=5A+2(1-A)$

$\Rightarrow 8=5A+2-2A$

$\Rightarrow 8=3A+2$

$\Rightarrow 6=3A$

$\Rightarrow A=1/2$

substituting back for $B$

$\Rightarrow B=1-1/2$

$\Rightarrow B=1/2$

final answer: $(A,B)=(1/2,1/2)$

can anyone tell me where I went wrong?

1. Isolate a variable in one of the equations

2. substitute that isolated variable into equation two so that you're second equation is in one variable

3. solve equation two for the second unknown variable

4. use the result from the second equation to find out what your original isolated variable equals.

here's my problem and what I tried:

equation 1: $1=A+B$

equation 2: $8=5A+2B$

Isolating $B$

$B=1-A$

Solving for $A$

$8=5A+2(1-A)$

$\Rightarrow 8=5A+2-2A$

$\Rightarrow 8=3A+2$

$\Rightarrow 6=3A$

$\Rightarrow A=1/2$

substituting back for $B$

$\Rightarrow B=1-1/2$

$\Rightarrow B=1/2$

final answer: $(A,B)=(1/2,1/2)$

can anyone tell me where I went wrong?

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