Confirm that the Integral Test can be applied to the series. Then use the Integral Test to determine the convergence or divergence of the series.sum_{n=1}^inftyfrac{arctan n}{n^2+1}

beljuA

beljuA

Answered question

2020-11-08

Confirm that the Integral Test can be applied to the series. Then use the Integral Test to determine the convergence or divergence of the series.
n=1arctannn2+1

Answer & Explanation

hesgidiauE

hesgidiauE

Skilled2020-11-09Added 106 answers

Gived: 
Verify if the series may be used with the Integral Test. The Integral Test can then be used to assess if the series is converging or diverging.
Given: we have n=1tan1nn2+1 
The integral test is applicable when the function is positive and rising for the reason that nN 
we can write it as 
1tan1xx2+1dx=lima1atan1xx2+1 
let, 
u=tan1x 
du=1x2+1 
when x=1 then u=tan1xu=π4 
when x=a then u=tan1a 
the integral becomes 
limaπ4tan1audu=lima[u22]π4tan1a 
=lima12(tan1a)212(π4)2 
[limatan1a=tan1=π2] 
limaπ4tan1audu=12((π2)2((π4)2)) 
=12(π24π216) 
=3π232 
In this instance, the series converges.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-12-17Added 2605 answers

Answer is given below (on video)

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