Use the first derivatives test to find local exterma of

Daniell Phillips

Daniell Phillips

Answered question

2021-12-10

Use the first derivatives test to find local exterma of f(x)=x312x on R

Answer & Explanation

Raymond Foley

Raymond Foley

Beginner2021-12-11Added 39 answers

Step 1
We have to use the first derivative test to find the local exterma
The given expression is
f(x)=x312x
Step 2
we have
f(x)=x312x
differentiate with respect to x
f(x)=3x212
put f'(X)=0
3x212=0
divide by 3 on both sides
x24=0
x222=0
(x+2)(x-2)=0
x=2 OR x=-2
Step 3
So, we have local minima at x=2
put x=2 in f(x)
f(2)=23122
f(2)=8-24=-16
local minima at x=2 is -16
We have local maxima at x=-2
put x=-2 in f(x)
f(2)=2312(2)
f(2)=-8+24=16
Local maxima at x=-2 is 16

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