Solve the following quadratic equation by factorization method 4x^{2}-4ax+(a^{2}-b^{2})=0

Jessie Lee

Jessie Lee

Answered question

2021-12-10

Solve the following quadratic equation by factorization method
4x24ax+(a2b2)=0

Answer & Explanation

Elois Puryear

Elois Puryear

Beginner2021-12-11Added 30 answers

Step 1 Given
4x24ax+(a2b2)=0
Step 2 solving
Here, constant term =(a2b2)=(ab)(a+b)
and, Coefficient of middle term =-4a
Also, Coefficient of the middle term -4a=-[2(a+b)+2(a-b)]
4x24ax+(a2b2)=0
4x2{2(a+b)+2(ab)}x+(a+b)(ab)=0
4a22(a+b)x2(ab)x+(a+b)(ab)=0
{4x22(a+b)x}{2(ab)x(a+b)(ab)}=0
2x(2x(a+b)(ab)){2x(a+b)}=0
{2x(a+b)}{2x(ab)}=0
{2x(a+b)}=0or,{2x(ab)}=0
2x=a+b or, 2x=a-b
x=a+b2 or, x=ab2.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?