Find the absolute extremum f(x)=\sin x (30,120)

fanyattehedzg

fanyattehedzg

Answered question

2021-12-11

Find the absolute extremum
f(x)=sinx (30,120)

Answer & Explanation

Pansdorfp6

Pansdorfp6

Beginner2021-12-12Added 27 answers

Step 1
Given function is
f(x)=sinx,[30,120]
Differentiating with respect to x, we get
f(x)=cosx
Firstly, we find critical points of f(x) by solving f'(x)=0
f'(x)=0
cosx=0
x=90
Step 2
Now, we find value of f(x) at critical points and end-points of given interval.
f(30)=sin30=12
f(90)=sin90=1
f(120)=sin120=32
Step 3
Ans:
Absolute maximum value of given function is 1 and absolute minimum value of f(x) is 1/2

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