# The Ocoriee Company somethimes makes printing errors in its advertisin

The Ocoriee Company somethimes makes printing errors in its advertising in the next issue of the paper "The managing editor has done a study of this problem and found the following data:
$\begin{array}{|c|c|} \hline \text{Number of Errors}&0&1&2&3&4\\ \hline \text{Probability}&0.56&0.21&0.13&0.07&0.03\\ \hline \end{array}$
the probability that the next issue of the paper will have at least 1 error is
Select:
a. 0.21
b. 0.77
c. 0.56
d. 0.44

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Step 1
Given:
Probability distribution of printing errors in the paper.
The probability that the next issue of the paper will have at least 1 error is obtained as below:
$$\displaystyle{P}{\left({X}\geq{1}\right)}={1}-{P}{\left({X}{<}{1}\right)}$$
$$\displaystyle={1}-{P}{\left({X}={0}\right)}$$
$$\displaystyle={1}-{0.56}$$
$$\displaystyle={0.44}$$
Thus, the probability that the next issue of the paper will have at least 1 error is 0.44.
Step 2
Option d. The probability that the next issue of the paper will have at least 1 error is 0.44.