Step 1

Given:

Probability distribution of printing errors in the paper.

The probability that the next issue of the paper will have at least 1 error is obtained as below:

\(\displaystyle{P}{\left({X}\geq{1}\right)}={1}-{P}{\left({X}{<}{1}\right)}\)

\(\displaystyle={1}-{P}{\left({X}={0}\right)}\)

\(\displaystyle={1}-{0.56}\)

\(\displaystyle={0.44}\)

Thus, the probability that the next issue of the paper will have at least 1 error is 0.44.

Step 2

Answer:

Option d. The probability that the next issue of the paper will have at least 1 error is 0.44.