Find the absolute maximum and absolute minimum values of the function : f(x)=x4−8x2−10 on interval = [-3,4]

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Find the absolute maximum and absolute minimum values of the function f(x)=x4−8x2−10 on the interval [-3,4] as follows.  On the interval [-3,4], the critical points of the function f(x)=x4−8x2−10 are x=-2, x=0 and x=2.  Now evaluate the function at the critical points and at the endpoints x=-3 and x=4 as shown below.  f(−3)=(−3)4−8(−3)2−10=81−72−10=−1  f(−2)=(−2)4−8(−2)2−10=16−32−10=−26  f(0)=(0)4−8(0)2−10=0−0−10=−10  f(2)=(2)4−8(2)2−10=16−32−10=−26  f(4)=(4)4−8(4)2−10=256−128−10=118  Comparing the above values, it is clear that the absolute maximum and minimum of f on the interval [-3,4] are,  Absolute maximum : (x, f(x))=(4,118)  Absolute minima : (x,f(x))=(-2, -26), (x, f(x))=(2, -26)

Find the absolute maximum and absolute minimum values of the

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