Find the limits lim_{xrightarrow9}frac{sin(sqrt x-3)}{x-9}

Find the limits
$\underset{x\to 9}{lim}\frac{\mathrm{sin}\left(\sqrt{x}-3\right)}{x-9}$
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estenutC
Find the limit,
$\underset{x\to 9}{lim}\frac{\mathrm{sin}\left(\sqrt{x}-3\right)}{x-9}$
Here we have indeterminate form $\frac{0}{0}$
So, apply the LHospital