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Given: lim(x,y)→(2,0)1−cosyxy2 we will choose y=mx when y→0 then x→0.. lim(x,y)→(2,0)1−cosyxy2 =limx→01−cos(mx)x(mx)2 =limx→0msinmx3m2x2 =limx→0mcosmx6mx =limx→0−msinmx6 =0
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Solve limx→1(x4−4)(x2−3x+2)
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