a) Two numbers when multiplied equals 36, one number is x and the othe

gainejavima

gainejavima

Answered question

2021-12-03

a) Two numbers when multiplied equals 36, one number is x and the other number is greater than x by 5
Represent the information given in equation form
Express as a quadratic equation
Solve the quadratic equation to find possible values for x
If told that the two number were positive, give the values of the two original numbers.
b) Solve the following quadratic equations ( use the quadratic formula)
1) 2x26x20=0
2) 6x25x6=0

Answer & Explanation

giskacu

giskacu

Beginner2021-12-04Added 22 answers

Step 1
Let x be the one numbers.
Other number is greaters than x by 5
So other number is x+5
The two numbers are x and x+5
Product of two numbers is 36
x(x+5)=36
x2+5x=36
x2+5x36=0
Quadratic equation is x2+5x36=0
Formula for solving second degree
Quadratic equation is (ax2+bx+c=0)
x=b±b24ac2a
Step 2
x2+5x36=0
a=1, b=5, c=36
x=5±524x1x36{2x1}5±25+1442
x=5±1692=5±1692
x=5+132 or x=5132
x=4 or x=9
Possible values of x are x=4 and x=9
Given that two numbers were positive
So the value of x is 4
Other number is x+5=4+5=9
So the numbers are 4 and 9
Step 3
1) 2x26x20=0
x=b±b24ac2a=(6)±(6)24x×2×202×2
=6±36+1604=6±144
x=6+144=5 or x=6144=2
Possible values of x are 5 and -2
2) 6x25x6=0
x=(5)±(5)24×6×62×6
=5±25+14412=5±1312
x=5+

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?