Find parametric equations for the line that passes through the

Nefissi8u 2021-12-02 Answered
Find parametric equations for the line that passes through the point (5, 2) and is parallel to the line
y=72x2
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Expert Answer

Marian Tucker
Answered 2021-12-03 Author has 15 answers

Step 1
The given equation of line
y=72x2
comaparing with the y=mx+b, we get
m=72 and b=2
The slope of the line is 72
Given that the line passes through the point (5, 2) is parallel to the line y=72x2
We know that the slope of parallel line is same
So, the line passes trough the point (5, 2) has slope m=72
Step 2
using point slope formula,
yy1=m(xx1)
Here m=72, (x1, y1)=(5, 2)
y2=72(x5)
y27=x52=t(t)
Now, y27=ty2=7ty=27t
and x52=t
x=2tx=5+2t
so, parametric equations for the line that passes through the point (5, 2) is
y=27t, x=5+2t
This is the required answer.

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