Evaluate the following limits. lim_{xrightarrow-3}frac{sin(x+3)}{x^2+8x+15}

Emeli Hagan 2021-02-18 Answered
Evaluate the following limits.
limx3sin(x+3)x2+8x+15
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Expert Answer

averes8
Answered 2021-02-19 Author has 92 answers
To evaluate
limx3sin(x+3)x2+8x+15
Using, limx3sin(x+3)x2+8x+15=limx3sin(x+3)x2+3x+5x+15
=limx3sin(x+3)x(x+3)+5(x+3)
=limx3sin(x+3)(x+3)(x+5)
=limh0[sinhh×1h+2]
=12
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Jeffrey Jordon
Answered 2022-04-01 Author has 2064 answers

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