Evaluate the following limits. lim_{xrightarrow-3}frac{sin(x+3)}{x^2+8x+15}

Emeli Hagan

Emeli Hagan

Answered question

2021-02-18

Evaluate the following limits.
limx3sin(x+3)x2+8x+15

Answer & Explanation

averes8

averes8

Skilled2021-02-19Added 92 answers

To evaluate
limx3sin(x+3)x2+8x+15
Using, limx3sin(x+3)x2+8x+15=limx3sin(x+3)x2+3x+5x+15
=limx3sin(x+3)x(x+3)+5(x+3)
=limx3sin(x+3)(x+3)(x+5)
=limh0[sinhh×1h+2]
=12
Jeffrey Jordon

Jeffrey Jordon

Expert2022-04-01Added 2605 answers

Answer is given below (on video)

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