# Find the derivative of y=\sqrt{x}.

Find the derivative of $y=\sqrt{x}$.
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Vaing1990
Firstly, convert the square root:
$y=\sqrt{x}={x}^{\frac{1}{2}}$
${y}^{\prime }=\frac{1}{2}{x}^{\frac{1}{2}-1}=\frac{1}{2}{x}^{\frac{1}{2}-\frac{2}{2}}=\frac{1}{2}{x}^{-\frac{1}{2}}=\frac{1}{2{x}^{\frac{1}{2}}}=\frac{1}{2\sqrt{x}}$