Use L'Hospital Rule to evaluate the following limits. lim_{xrightarrow0}frac{tanh^{-1}x}{tan(pi x/2)}

Amari Flowers 2020-12-05 Answered
Use LHospital
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Expert Answer

yunitsiL
Answered 2020-12-06 Author has 108 answers
Given limit function is limx0tanh1xtan(πx/2)
limx0tanh1xtan(πx/2)=tanh1(0)tan(0)=00
Apply LHopitals Rule.
limx0tanh1xtan(πx/2)=limx02πsec2(πx2)(1x2)
=2π
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