Evaluate the following limits. lim_{(x,y,z)rightarrow(0,1,0)}ln(1+y)e^{xz}

e1s2kat26

e1s2kat26

Answered question

2020-11-08

Evaluate the following limits.
lim(x,y,z)(0,1,0)ln(1+y)exz

Answer & Explanation

Nathanael Webber

Nathanael Webber

Skilled2020-11-09Added 117 answers

Consider the following limit:
lim(x,y,z)(0,1,0)ln(1+y)exz=ln(1+1)e0×0
=ln(2)e0
=ln(2)×1
=ln(2)
Hence, the solution is lim(x,y,z)(0,1,0)ln(1+y)exz=ln(2)
Jeffrey Jordon

Jeffrey Jordon

Expert2022-08-24Added 2605 answers

Answer is given below (on video)

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