Find the equation of thequadratic function whose graph is a

Sheelmgal1p

Sheelmgal1p

Answered question

2021-12-04

Find the equation of thequadratic function whose graph is a parabola coordinating the points (0,4), (2, 10), and (-1, 10)
The equation of the quadratic function whose graph is a parabola containing the given points is yB
(type an equadratic using x and the vartable)

Answer & Explanation

Coldst

Coldst

Beginner2021-12-05Added 18 answers

The general equation of a parabola is y=ax2+bx+c.
Substitute the 3 points in the equation, we get
3 linea y equations. By solving these equations
we will get the result.
The general equation of a parabola is
y=ax2+bx+ci
Substitute the points in i we get
3 equations.
(0,4)
4=a×o2+b×cc=4
(2,10)
10=a×22+b×2+c4a+2b+4=10
4a+2b=104
a4+2b=6
2(2a+b)=6
2a+b=62=3
2a+b=31
(-1, 10)
10=a×(122+b×1+cab+c=10
ab+4=10
ab=104=6
ab=52
1+22a+b=3+
ab=6
3a=9
a=93=3
Substitute a=3 in 2, we get
3b=6
b=36=3
Equation of the parabola is
y=3x23x+4

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