Consider the quadratic function.f(x)=−(x+4)(x−1)a.What are the x-intercepts and y-intercepts?b.What is the equation of the axis of symmetry?c. What are the coordinates of the vertex? yurm quadratic function,f(x)=−(x+4)(x−1)1) For x-intercepts, put&nbsp;f(x)=0⇒−(x+4)(x−1)=0=x+4=0&nbsp;&nbsp;and&nbsp;&nbsp;x−1=0x=4&nbsp;&nbsp;and&nbsp;&nbsp;x=1are&nbsp;(−4,0)&nbsp;&nbsp;and&nbsp;&nbsp;(1,0)Thus, x-intercepts are&nbsp;(−4,0)&nbsp;&nbsp;and&nbsp;&nbsp;(1,0)For y intercepts put&nbsp;x=0&nbsp;in&nbsp;f(x)f(x)=+(0+4)(x−1)=−4Thus, y-intercepts is (0, -4)2)Reusiting the function as below:f(x)=−(x+4)(x−1)=−(x2−x+4x−4)f(x)=−(x2+3x−4)f(x)=−(x2+3x+(32)2−(322)+4&nbsp;f(x)=−(x+32)2+4Comparising it with vertex form,&nbsp;y=a(z−h)2+khere,&nbsp;a=−1,h=−32&nbsp;&nbsp;and&nbsp;&nbsp;k=4Thus, axis of symmetry is&nbsp;x=h=−323) Vertex coordinates:&nbsp;(h,k)=(−32,4&nbsp;)

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Consider the quadratic function.f(x)=−(x+4)(x−1)a.What are the x-intercepts and y-intercepts?b.What is the equation of the axis of symmetry?c. What are the coordinates of the vertex? yurm quadratic function,f(x)=−(x+4)(x−1)1) For x-intercepts, put&amp;nbsp;f(x)=0⇒−(x+4)(x−1)=0=x+4=0&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;x−1=0x=4&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;x=1are&amp;nbsp;(−4,0)&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;(1,0)Thus, x-intercepts are&amp;nbsp;(−4,0)&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;(1,0)For y intercepts put&amp;nbsp;x=0&amp;nbsp;in&amp;nbsp;f(x)f(x)=+(0+4)(x−1)=−4Thus, y-intercepts is (0, -4)2)Reusiting the function as below:f(x)=−(x+4)(x−1)=−(x2−x+4x−4)f(x)=−(x2+3x−4)f(x)=−(x2+3x+(32)2−(322)+4&amp;nbsp;f(x)=−(x+32)2+4Comparising it with vertex form,&amp;nbsp;y=a(z−h)2+khere,&amp;nbsp;a=−1,h=−32&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;k=4Thus, axis of symmetry is&amp;nbsp;x=h=−323) Vertex coordinates:&amp;nbsp;(h,k)=(−32,4&amp;nbsp;)

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yurm quadratic function,&amp;nbsp;f(x)=−(x+4)(x−1)&amp;nbsp;1) Add &amp;nbsp;f(x)=0&amp;nbsp;to the x-intercepts.arrow−(x+4)(x−1)=0&amp;nbsp;=x+4=0&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;x−1=0&amp;nbsp;x=4&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;x=1&amp;nbsp;are&amp;nbsp;(−4,0)&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;(1,0)&amp;nbsp;Thus, x-intercepts are&amp;nbsp;(−4,0)&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;(1,0)&amp;nbsp;For y intercepts put&amp;nbsp;x=0&amp;nbsp;in f(x)&amp;nbsp;f(x)=+(0+4)(x−1)=−4&amp;nbsp;Thus, y-intercepts is (0, -4)&amp;nbsp;2) Using the function again as follows:f(x)=−(x+4)(x−1)=−(x2−x+4x−4)&amp;nbsp;f(x)=−(x2+3x−4)&amp;nbsp;f(x)=−(x2+3x+(32)2−(322)+4&amp;nbsp;&amp;nbsp;f(x)=−(x+32)2+4&amp;nbsp;Comparising it with vertex form,&amp;nbsp;y=a(z−h)2+k&amp;nbsp;here,&amp;nbsp;a=−1,h=−32&amp;nbsp;&amp;nbsp;and&amp;nbsp;&amp;nbsp;k=4&amp;nbsp;Thus, axis of symmetry is&amp;nbsp;x=h=−32&amp;nbsp;3) Vertex coordinates:&amp;nbsp;(h,k)=(−32,4&amp;nbsp;

1. Consider the quadratic function.f(x)=-(x+4)(x-1)a.W

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