Question

A normal distribution mu = 30 and sigma = 5. (b)Find the z score corresponding to x =42.

Normal distributions
ANSWERED
asked 2021-02-05
A normal distribution \(\mu = 30\) and \(\sigma = 5\).
(b)Find the z score corresponding to \(x =42\).

Answers (1)

2021-02-06
\(\mu = 30\), \(\sigma = 5\), \(x =25\).
We use the formula for normal distribution:
\(z = \frac{x-\mu}{\sigma}\)
\(z=\frac{25-30}{5}\)
\(z=-1.0\)
The z score corresponding to \(x = 25\) for normal distribution with \(\mu = 30\), \(\sigma =5\) is -1.0.
0
 
Best answer

expert advice

Have a similar question?
We can deal with it in 3 hours

Relevant Questions

asked 2021-02-05
zScore and Raw Score A normal distribution has \(\mu = 30\) and \(\sigma = 5\).
(a)Find the z score corresponding to \(x =25\).
asked 2020-12-28
Basic Computation: zScore and Raw Score A normal distribution has \(\mu = 30\) and \(\sigma = 5\).
(c)Find the raw score corresponding to \(z =-1.3\).
asked 2021-03-06
A normal distribution has \(\mu = 30\) and \(\sigma = 5\).
(c)Find the raw score corresponding to \(z =-2\).
asked 2021-06-05
Use the following Normal Distribution table to calculate the area under the Normal Curve (Shaded area in the Figure) when \(Z=1.3\) and \(H=0.05\);
Assume that you do not have vales of the area beyond \(z=1.2\) in the table; i.e. you may need to use the extrapolation.
Check your calculated value and compare with the values in the table \([for\ z=1.3\ and\ H=0.05]\).
Calculate your percentage of error in the estimation.
How do I solve this problem using extrapolation?
\(\begin{array}{|c|c|}\hline Z+H & Prob. & Extrapolation \\ \hline 1.20000 & 0.38490 & Differences \\ \hline 1.21000 & 0.38690 & 0.00200 \\ \hline 1.22000 & 0.38880 & 0.00190 \\ \hline 1.23000 & 0.39070 & 0.00190 \\ \hline 1.24000 & 0.39250 & 0.00180 \\ \hline 1.25000 & 0.39440 & 0.00190 \\ \hline 1.26000 & 0.39620 & 0.00180 \\ \hline 1.27000 & 0.39800 & 0.00180 \\ \hline 1.28000 & 0.39970 & 0.00170 \\ \hline 1.29000 & 0.40150 & 0.00180 \\ \hline 1.30000 & 0.40320 & 0.00170 \\ \hline 1.31000 & 0.40490 & 0.00170 \\ \hline 1.32000 & 0.40660 & 0.00170 \\ \hline 1.33000 & 0.40830 & 0.00170 \\ \hline 1.34000 & 0.41010 & 0.00180 \\ \hline 1.35000 & 0.41190 & 0.00180 \\ \hline \end{array}\)
...