Evaluate the following limits. lim_{(x,y)rightarrow(0,pi)}frac{cos xy+sin xy}{2y}

FizeauV 2021-02-25 Answered
Evaluate the following limits.
lim(x,y)(0,π)cosxy+sinxy2y
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Expert Answer

Asma Vang
Answered 2021-02-26 Author has 93 answers
Given,
lim(x,y)(0,π)cosxy+sinxy2y
By applying the limit, we get
lim(x,y)(0,π)cosxy+sinxy2y=cos(0π)+sin(0π)2π
=cos(0)+sin(0)2π
=1+02π
=12π
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Jeffrey Jordon
Answered 2022-04-01 Author has 2047 answers

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