Find the limits: lim_{xrightarrow2}frac{sqrt{x^2+12}-4}{x-2}

Yasmin 2020-11-10 Answered
Find the limits:
limx2x2+124x2
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Expert Answer

firmablogF
Answered 2020-11-11 Author has 92 answers

We have to find limits:
limx2x2+124x2
Since we have an indeterminate form of type 00, we can apply the L'hospital rule:
limx2x2+124x2=limx2ddx(x2+124)ddx(x2)
limx22x2x2+121
limx2xx2+12=222+12=24+12
=216=24=12
limx2x2+124x2=12

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