Use the method of your choice to evaluate the following limits. lim_{(x,y)rightarrow(0,1)}frac{ysin x}{x(y+1)}

Zoe Oneal 2021-01-02 Answered
Use the method of your choice to evaluate the following limits.
lim(x,y)(0,1)ysinxx(y+1)
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Expert Answer

aprovard
Answered 2021-01-03 Author has 94 answers
Given limits:
lim(x,y)(0,1)ysinxx(y+1)
We have to evaluate the limit.
The limit is computed as follows:
lim(x,y)(0,1)ysinxx(y+1)=limx0sinxxlimy1yy+1
Substitutes the limits:
We know that: limθ0sinθθ=1
lim(x,y)(0,1)ysinxx(y+1)=1×11+1
lim(x,y)(0,1)ysinxx(y+1)=12
Therefore, the value of lim(x,y)(0,1)ysinxx(y+1) is 12
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Jeffrey Jordon
Answered 2022-04-01 Author has 2047 answers

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