inlays85k5
2021-11-30
Answered

Represent the plane curve by a vector-valued function $y={(x-2)}^{2}$

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Egreane61

Answered 2021-12-01
Author has **16** answers

Step 1

$y={(x-2)}^{2}$

Now let

$x\left(t\right)=t$

Now put$x\left(t\right)=t$ in $y={(x-2)}^{2}$ , we get

$y={(t-2)}^{2}$

Step 2

$r\left(t\right)=x\left(t\right)i+y\left(t\right)j$

$\Rightarrow r\left(t\right)=ti+{(t-2)}^{2}j$

Now let

Now put

Step 2

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