Let r(t) and u(t) be vector-valued functions whose limits exist

yapafw

yapafw

Answered question

2021-11-28

Let r(t) and u(t) be vector-valued functions whose limits exist as t c. Prove that
limtc[r(t)×u(t)]=limtc×limtcu(t)

Answer & Explanation

William Yazzie

William Yazzie

Beginner2021-11-29Added 20 answers

Step 1
Given
r(t) and u(t) be vector valued function whose lint exist as tc
To prove
limtc[r(t)×u(t)]=limtcr(t)×limtcu(t)
Step 2
Dot product
If a=a1i+a2j+a3k and b=b1i+b2j+b3k
a×b=a1b1+a2b2+a3b3
Step 3
Let r(t)=a(t)i+b(t)j+c(t)k
u(t)=m(t)i+n(t)j+p(t)k
On taking L.H.S
limtc[r(t)×u(t)]=limtc(a(t)i+b(t)j+c(t)k)×(m(t)i+n(t)j+p(t)k)
=limtc(a(t)m(t)+b(t)n(t)+c(t)p(t))
=limtc(a(t)m(t))+limtc(b(t)n(t))+limtc(c(t)p(t))
Since limit exist as t tends to c.
=a(c)m(c)+b(c)n(c)+c(c)p(c)
limtcpr(t)×u(t)]=a(c)m(c)+b(c)n(c)+c(c)p(c)
Now taking R.H.S

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