Evaluate the following integrals. int_0^1frac{16^x}{4^{2x}}dx

sjeikdom0 2021-03-09 Answered
Evaluate the following integrals.
0116x42xdx
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Expert Answer

toroztatG
Answered 2021-03-10 Author has 98 answers
To integrate: 0116x42xdx
Solution:
0116x42xdx
Om simplifying further we get:
0116x42xdx=01(42)x42xdx
=0142x42xdx
=011dx
=[x]01
=[10]
=1
Result: 0116x42xdx=1
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