Evaluate the integrals. int e^{lnsqrt x}dx

Jerold 2020-10-18 Answered
Evaluate the integrals.
elnxdx
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Expert Answer

Fatema Sutton
Answered 2020-10-19 Author has 88 answers
Given,elnxdx
On simplification, we get
elnxdx=xdx   [elnx]
Now on integrating, we get
xdx=x1/2dx
=x3/23/2+C  [xndx=xn+1n+1]
=23x3/2+C
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