Evaluate the integrals. int e^{lnsqrt x}dx

Jerold

Jerold

Answered question

2020-10-18

Evaluate the integrals.
elnxdx

Answer & Explanation

Fatema Sutton

Fatema Sutton

Skilled2020-10-19Added 88 answers

Given,elnxdx
On simplification, we get
elnxdx=xdx   [elnx]
Now on integrating, we get
xdx=x1/2dx
=x3/23/2+C  [xndx=xn+1n+1]
=23x3/2+C

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