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ffortunyu

Answered question

2021-11-20

A 4 A current moves along a wire. What is the current flowing through the additional wire that sends out twice as much charge in half the time?

James Kilian

Beginner2021-11-21Added 20 answers

We have following data of current in first wire:
Current

I_{1} = \frac{Q_{1}}{t_{1}} = 4 A

The current in a second wire that delivers twice as much charge in half the time can be calculate as

I_{2}

In general we have:

I = \frac{Q}{t}

Q_{2} = 2 Q_{1}

and

t_{2} = \frac{t_{1}}{2}

, we get:

I_{2} = \frac{Q_{2}}{t_{2}} = \frac{2 Q_{1}}{\frac{t_{1}}{2}} = 4 \frac{Q_{1}}{t_{1}}

I_{2} = 16 A

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