A wire carries a 4 A current. What is the current in a second wire that delivers

ffortunyu 2021-11-20 Answered
A wire carries a 4 A current. What is the current in a second wire that delivers twice as much charge in half the time?

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James Kilian
Answered 2021-11-21 Author has 7685 answers
We have following data of current in first wire:
Current \(\displaystyle{I}_{{1}}={\frac{{{Q}_{{1}}}}{{{t}_{{1}}}}}={4}{A}\)
The current in a second wire that delivers twice as much charge in half the time can be calculate as \(\displaystyle{I}_{{2}}\)
In general we have:
\(\displaystyle{I}={\frac{{{Q}}}{{{t}}}}\)
If \(\displaystyle{Q}_{{2}}={2}{Q}_{{1}}\) and \(\displaystyle{t}_{{2}}={\frac{{{t}_{{1}}}}{{{2}}}}\), we get:
\(\displaystyle{I}_{{2}}={\frac{{{Q}_{{2}}}}{{{t}_{{2}}}}}={\frac{{{2}{Q}_{{1}}}}{{{\frac{{{t}_{{1}}}}{{{2}}}}}}}={4}{\frac{{{Q}_{{1}}}}{{{t}_{{1}}}}}\)
\(\displaystyle{I}_{{2}}={16}{A}\)
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