One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm. Det

dictetzqh

dictetzqh

Answered question

2021-11-21

One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm. Determine the initial and final values of n associated with this emission.

Answer & Explanation

Othrom

Othrom

Beginner2021-11-22Added 15 answers

Writing out known values:
Emission line wavelength: λ=93.07 nm=93.07×109 m
This wavelength corresponds with the ultraviolet region of the electromagnetic spectrum.
Rydverg constant: RH=1.096776×107m1
Determining the final value of n associated with this emission
For the hydrogen atom emission spectrum, wavelengths in the ultraviolet region are observed in the Lyman series
For the Lyman series of emission lines nf=1
Calculating the initial value of n associated with emission:
1λ=(RH)(1nf21ni2)
1ni2=1λ×RH1nf2
1ni2=193.07×109 m×1.096776×107 m1112
1ni2=0.02
ni=7

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