In an L-R-C series circuit, L = 0.280 H and C=4.00μF. The voltage amplitude of the source is 120 V. (a) What is the resonance angular frequency of the circuit? (b) When the source operates at the resonance angular frequency, the current amplitude in the circuit is 1.70 A. What is the resistance R of the resistor? (c) At the resonance angular frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?

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Zachary Pickett · Accepted Answer

a) Use the expression for angular resonance frequency from section 31.5  ω0=1LC=1(0.280 H)(4.00E−6F)  b) Recall that at resonance, Z=R  V=IZ→IR→VI=R  ⇒120 V1.70 A=70.6  c) At resonance VR is the same as the source. VL and VC are the same, and VL−VC=0  VR=120.V  VL=IωL=(1.70A)(945rads)(0.280H)=450.V  VC=IωC=1.70A(945rads)(4.00R−6F)=450.V  Result:  a)945 rad/s  b) 70.6 w  c) 120 V/450 V/450 V

In an L-R-C series circuit, L = 0.280 H and C=4.00\mu F. The voltage ampli

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